напримепь есть саыт xxx.com/news.php?id=2

кояда зделаеш ххх.com/news.php?id=2

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'tw'' at line 1

Warning: mysql_fetch_row(): supplied argument is not a valid MySQL result resource in /home/twt/public_html/cp/lib/db.php on line 28


а кояда ххх.com/news.php?id=2+union+select+0

Forbidden

You don't have permission to access /browse.php on this server.

что зделать ?